Question

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Answer 1

$\orange{\underline{\huge{\bold{\textit{\green{\bf{QUESTIONS}}}}}}}$

In an experiment to measure the specific heat capacity of copper, 0.02 kg of water at 70°C is poured into a copper calorimeter (with a stirrer) of mass 0.16 kg at 15°C. After stirring, the final temperature is found to be 45°C. If the specific heat of water is 4,200 J/kg/°C,

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WATER:-

Mass :- 0.02 kg at 70°C

Specific Heat Of Water is 4,200 J/kg°C,

COPPER:-

MASS:- mass 0.16 kg at 15°C

Temperatures r according to the part !

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what is the quantity of heat released per kg of water per 1°C fall in temperature?

Calculate the heat energy released by water in the experiment in cooling from 70°C to 45°C.

Assuming that the heat released by water is entirely used to raise the temperature of calorimeter from 15°C to 45°C) calculate the specific heat capacity of copper.

$\huge\red{\boxed{\huge\mathbb{\red A \pink{N}\purple{S} \blue{W} \orange{ER}}}}$

${\blue{\star{\red{Part \: 1 :- What \: is \: the \: quantity \: of heat \: released \: per \: kg \: of \: w ater \: per \: 1°C \: fall \: in \: temperature }}}}$

$\orange{Specific \: \: Heat}$

It is the amount of the heat released by unit mass of the body per 1°C fall in temperature.

It is the amount of the heat absorbed by the unit mass of the body per 1°C rise in temperature

So quantity of heat released per kg of water per 1°C fall in temperature is equal to the specific heat of the water which is 4,200 J/kg°C,

${\red{\star{\blue{Part \:2 :-\: Calculate \: the \: heat \: energy \: released \: by \: water \: in \: the \: experiment \: in \: cooling \: from \: 70°C \: to \: 45°C. }}}}$

MASS OF WATER --> 0.02 kg

INITIAL TEMPERATURE--> 70°C

FINAL TEMPERATURE--> 45°C

CHANGE IN TEMPERATURE--> (45-70)°C =(- 25)°C

SPECIFIC HEAT OF WATER--> 4200 J/ kg °C

$Q = mc\triangle T \\ \\ Q = 0.02 \times 4200 \times ( -25) \\ \frac{2}{100} \times 4200 \times( - 25) =Q \\ ( - 50) \times 42 = Q \\ Q = ( - 2100) \: joules$

NEGATIVE INDICATES THAT HEAT IS RELEASED BY THE BODY!

IT MEANS COOLING HAS BEEN TAKEN PLACED.

${\red{\star{\green{Part \:2 :-\:Assuming \: that \: the \: heat \: released \: by \: water}}}} \\ \\ {\green{is \: entirely \: used \: to \: raise \: the temp \: of \: calorimeter \: from \: 15°C \: to \: 45°C }} \\ \\{\green{ calculate \: the \: specific \: heat \: capacity \: of \: copper.}}$

MASS OF COPPER :- 0.16 kg

INITIAL TEMPERATURE:- 15°C

FINAL TEMPERATURE:- 45°C

CHANGE IN TEMPERATURE--> (45-15)°C = 30°C

AMOUNT OF HEAT RELEASED BY WATER --> 2100 J ( From second part)

$Q = mc\triangle T \\ \\ 2100 = 0.16 \times c \times 30 \\ 70 = 0.16 \times c \\ \\ c = \frac{7000}{16} \\ c = 437.5 \: \frac{J }{kg°C}$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: expert005$