Question

AB meets the x-axis at A and the y-acid at B. Write down the coordinates of A and B. Calculate the area of the triangle OAB, where O is the origin.

Class : 10​

Answer 1

Answer:

$Area\:of \:\triangle \:OAB = \frac{1}{2} xy$

Step-by-step explanation:

Here ,

AB meets the x-axis at A(x,0) and the y-axis at B(0,y).

∆OAB is a right angled triangle.

$Area \: \triangle OAB = \frac{1}{2}\times base\times height\\=\frac{1}{2} bh\\=\frac{1}{2} xy$

Example:

figure 2:

Consider the points A(0,4) and B(6,0) which form a triangle with origin O on a plane as shown in figure 2.

∆AOB is right angled triangle and the base is 6 units (i.e .,x coordinate) and height is 4 units (i.e., y coordinate )

$Area \: \triangle OAB = \frac{1}{2}\times base\times height\\=\frac{1}{2}\times 6\times 4\\=3\times 4\\=12 \: square\: units$

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Answer 2

Answer:

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