Question

ab-mn+an-bm
factorise it
​

Answer 1

Answer:

(a-m)*(b+n)

Step-by-step explanation:

So, rearrange it to get ab+an-mn-mb.

Now, from ab+an, take a common and you get a(b+n).

From, -mn-mb, take -m common and you get -m(n+b) or -m(b+n).

So, you have a(b+n) - m(b+n)

Again you can take b+n common and you get (b+n)*(a-m) or (a-m)*(b+n)

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