Question

AB parallel CD,BC parallel RD find x​

Answer 1

Answer:

From the given figure we know that AB and CD are parallel line and BC is a transversal We know that ∠BCD and ∠ABC are alternate angles So we can write it as ∠BCD + ∠ABC = xo We also know that BC || ED and CD is a transversal

From the figure we know that ∠BCD and ∠EDC form a linear pair of angles So it can be written as ∠BCD + ∠EDC = 180o By substituting the values we get ∠BCD + 75o = 180o On further calculation we get ∠BCD = 180o – 75o By subtraction ∠BCD = 105o

From the figure we know that ∠BCD and ∠ABC are vertically opposite angles So we get ∠BCD = ∠ABC = x = 105o ∠ABC = x = 105°

Therefore, the value of x is 105°

Answer 2

Answer:

Angle x = 105 degree

Step-by-step explanation:

Given- angle CDE = 75 degree

angle BCD + angle CDE = 180 [ by co-interior angle]

angle BCD+ 75 = 180

angle BCD= 180-75 = 105 degree

Now, angle ABC = angle BCD = 105 degree    [by alternate interior angle]