ab parallel CF and BC parallel ed prove that angle abc = angle fde
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Step-by-step explanation:
given AB ║CF
BC║ED
to prove ABC=FDE
proof let BCD=∠1
ABC=∠1 [alternate interior angle]
if BC=ED
∠1=FDE[CORRESPONDING ANGLES ARE EQUAL]
BY 1 AND 2 W
∠ABC=∠BCD=∠FDE
∠ABC=∠FDE
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