ab parallel Ch and EF parallel BC find the value of x and y
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Answer:
∠x = 60°
y = 110°
Step-by-step explanation:
AB ║ CH
=> ∠AEF = 50°
in Δ AEG
∠y = 50° + 60° ( External angle of triangle = Sum of opposite internal angles)
=> y = 110°
∠EFC = 50° (opposite angles)
in Δ CGF
∠y = ∠x + 50°
=> 110° = ∠x + 50°
=> ∠x = 60°
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