Question

AB parallel to CD and P is any point shown in the figure . prove that angle ABP + angle BPD + angle CDP = 360°

Answer 1

at first draw the parralel line through p  

now,  

AB||EP

<ABP+<BPE=180°

and, EP||CD

<EPD+<CPD=180°

NOW, <ABP+<BPE+<EPD+<CPD=180°+180°

<ABP+<BPD+<CPD=360°(PROVED)

Answer 2

Answer:

here's the best answer