ab parallel to cd and t transversal cuts e and f if ef and fq are the bisectors of angle aef and eff prove ep parallel fq
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Step-by-step explanation:
AB parallel CD and let EF be the transversal
therefore angle EGB = angle GHD
(forming corresponding angles)
therefore angle GHD = 35°
angle GHD = angle PHQ.... opposite angles
therefore angle PHQ = 35°
In Δ PHQ, angle P = 90° and angle PHQ = 35°
therefore angle PQH = 55°
.......(remaining angle of a triangle)
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