AB parllel CD , angle BDC = 30 , angle =80 , find x,y,z .
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X=30°,Y=100°andZ=80°
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Answer:
x=30, y=70, z=110
Step-by-step explanation:
In the given trapezium,
AB parallel CD and consider AC as a traversal,
now angle CAD = ACD (alternate interior angles)
so, x = 30°
Consider the triangle ADC,
here the sum of all angles in this triangle is 180
so, x+y+80=180
=> y+110=180
=> y = 70°
now consider the triangle ABC
here also the sum of all interior angles of the triangle is 180
so, 30+y-30+z=180
=> y+z=180
=> 70+z=180
=> z=180-70
=> z=110°
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