Question

AB //PQ find the
value of x​

Answer 1

Answer:

It is given that AB∥PQ and EF is a transversal

from the figure we know that ∠CEB and ∠EFQ are corresponding angles

so we get

∠CEB=∠EFQ=75  degree

it can be written as

∠EFQ=75  degree

where

∠EFG+∠GFQ=75  degree

by substituting the values

25degree   +y   =75  degree

y   =50    

from the figure we know that ∠BEF and ∠EFQ are consecuting interior angles

so we get

∠BEF+∠EFQ=180  

by substituting the values

∠BEF+75  =180  

∠BEF=105  

we know that ∠BEF can be writte as

∠BEF=∠FEG+∠GEB  

105   =∠FEG+20

∠FEG=105   −20  

∠FEG=85  

According to the △EFG

we can write

x  +25   +∠FEG=180  

by substituting the values

x   +25  +85   =180  

x  =70  

therefore the value of x is 70

Step-by-step explanation:

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