Math, asked by Sony4420, 1 year ago

Ab=radus'r' of the cirxle.Find angle acb.O is the center of thecirxle

Answers

Answered by Anonymous
3

SOLUTION___◉‿◉

OA=0B=AB{ Given}

Therefore ∆OAB is an equilateral∆

Angle AOB=60°

We know, angle subtended at a point on a circle is half the angle subtended at the centre.

AngleACB= AngleADB÷2 = 60÷2= 30°

So,angle ACB=30° ans.

MARK BRAINLIEST✓✓

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