Ab=radus'r' of the cirxle.Find angle acb.O is the center of thecirxle
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SOLUTION___◉‿◉
OA=0B=AB{ Given}
Therefore ∆OAB is an equilateral∆
Angle AOB=60°
We know, angle subtended at a point on a circle is half the angle subtended at the centre.
AngleACB= AngleADB÷2 = 60÷2= 30°
So,angle ACB=30° ans.
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