Question

(ab)^x-2=(ba)^x-7.value of x?​

Answer 1

Answer:

$(ab) ^{x - 2} = (ba)^{x - 7} \\ \\ (ab)^{ x - 2} = - (ab)^{x - 7} \\ \\ \\ x - 2 = - x + 7 \\ \\ \\ \\ 2x = 9 \\ \\ x = \frac{9}{2}$

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