Question

ab(x²+y²)-xy(a²+b²) factorize​

Answer 1

➡ ab(x²+y²)-xy(a²+b²)

➡ abx²+aby²-a²xy-b²xy

➡ abx²-a²xy + aby² - b²xy

➡ ax(bx-ay) - by( -ay + bx)

➡ axbx-axay+byay-bybx

➡ (bx-ay)(ax-by)

Step-by-step explanation:

þLÈÄ§È MÄRK MÈ Ä§ ßRÄÌñLÌȧ† ✌✌✌

Answer 2

Answer:

hope it helps u

if so please mark me as the brainliest

thanks:)

Step-by-step explanation:

by multiplying everything, we get

=>abx²+aby²-a²xy-b²xy

=>abx²-a²xy + aby² - b²xy

=>ax(bx-ay) - by( -ay + bx)

=>axbx-axay+byay-bybx

=>(bx-ay)(ax-by)