Question

ab ya bato Ki ya konse building ha
《¤¤¤¤¤¤¤¤¤¤¤¤¤¤》
☆ Given :
Polynomial = 12x²-4x+3x-1 i.e.12x² -x -1

___________________________
☆ To Calculate :
Zeros of the polynomial 12x²-4x+3x-1.

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☆ Also To Verify :
Relationship between Zeros And Coefficient.

___________________________
¤ Relationship between
Zeros And Coefficients :
If a Polynomial is of the Form ax² + bx + c.

and it's zeros are α and β.

Then,

α + β = -b/a
and

αβ = c/a
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☆ Solution :
《♤ {Calculating Zeros}♤》
12x²-4x+3x-1

= 4x(3x - 1) + 1(3x - 1 )

= (3x - 1)(4x+1)

So,
Zeros of the given polynomial are 1/3 and -1/4.
●》α= 1/3 and β = -1/4
《♤{Verifying Releationship}♤》
\begin{gathered} \sf\alpha + \beta = \frac{1}{3} + ( \frac{ - 1}{4} ) \\ \\ = \frac{1}{3} - \frac{1}{4} \\ \\ = \frac{1}{12} = \bf- \frac{b}{a} \: \: \: \{verified \}\end{gathered}
α+β=
3
1
​
+(
4
−1
​
)
=
3
1
​
−
4
1
​

=
12
1
​
=−
a
b
​
{verified}
​


\begin{gathered} \sf\alpha \beta = \frac{1}{3} \times ( - \frac{1}{4} ) \\ \\ = - \frac{1}{12} = \bf \frac{c}{a} \: \: \: \: \{verified \}\end{gathered}
αβ=
3
1
​
×(−
4
1
​
)
=−
12
1
​
=
a
c
​
{verified}
​


___________________________I am a sk sabir boss
Given :-
Baichung’s father is 26 years younger than Baichung’s grandfather and 29 years older than Baichung. The sum of the ages of all the three is 135 years.

To Find :-
Age of each

Solution :-
Let the age of Baichung be B

Age of father = B + 26

Age of grandfather = B + 26 + 29

Age of grandfather = B + 55

Now

(B) + (B + 26) + (B + 55) = 135

3B + 81 = 135

3B = 135 - 81

3B = 54

B = 54/3

B = 18

Now

Age of Baichung = 18 years

Age of his father = 18 + 26 = 44 years

Age of grandfather = 18 + 55 = 73 years

​​

Answer 1

Answer:

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Answer 2

Answer:

kya kr rahay ho

what is this question