Question

AB12: A2 PQ43:P3 JK95: ?

1 point

L5

K5

J5

K4

​

Answer 1

Answer:

The Highest Common Factor is k.

Given:  

2k, 3k, 4k, 5k where k is positive

To find:  

HCF of the given series

Solution:

In order to find H.C.F., we need to find prime factors of each number,

Now, we get

k = 1 x k

2k = 2 x k

3k = 3 x k

4k = 4 x k

5k = 5 x k

From above mentioned prime factors, we know that k is the only common factor,  

Thus, H.C.F = k