Question

AB2 molecule with bond angle 60° and bond moment of
AB as 0.48 D, then observed dipolemoment of the
molecule is ​

Answer 1

In the given case:

Ionic Character= Theoretical dipole /observed dipole moment x100

Given: Theoretical dipole moment = 1.6x10^-19C x 1.61x10^-10m= 2.576x10^-29Cm

1D=2.22x10^-30Cm

Solution: Percent Ionic Character= 2.567x10^-30

0.38x3.33x10^-30x100= 5%