Question

Abag contain 3 red balls, 5 black balls and
4
White balls. A ball is crawn at randon
from the bag o find the probability of
getting a black ball​

Answer 1

1 upon 12....

hope it helps you dear

Answer 2

Step-by-step explanation:

Total no. of balls in the bag is 12 (3 red, 5 black and 4 white)

Solution(i):

No. of white balls in bag is 4

Therefore,

4

C

1

( Selecting 1 out of 4 items) times out of

12

C

1

( Selecting 1 out of 11 items) a white ball is picked.

Let E be the event of drawing a white ball from bag

We know that, Probability P(E) =

(Total no.of possible outcomes)

(No.of favorable outcomes)

=

12

C

1

4

C

1

=

12

4

=

3

1

Solution(ii):

No. of red balls in bag is 3

Therefore,

3

C

1

( Selecting 1 out of 3 items) times out of

12

C

1

( Selecting 1 out of 12 items) a red ball is picked.

Let E be the event of drawing a red ball from bag

We know that, Probability P(E) =

(Total no.of possible outcomes)

(No.of favorable outcomes)

=

12

C

1

3

C

1

=

12

3

=

4

1

Solution(iii):

No. of black balls in bag is 5

Therefore,

5

C

1

( Selecting 1 out of 5 items) times out of

12

C

1

( Selecting 1 out of 12 items) a black ball is picked.

Let E be the event of drawing a black ball from bag

We know that, Probability P(E) =

(Total no.of possible outcomes)

(No.of favorable outcomes)

=

12

C

1

5

C

1

=

12

5

Solution(iv):

No. of balls that are not red in bag is 9 (5 black, 4 white)

Therefore,

9

C

1

( Selecting 1 out of 9 items) times out of

12

C

1

( Selecting 1 out of 12 items) a ball that is not red is picked.

Let E be the event of drawing a ball that is not red from bag

We know that, Probability P(E) =

(Total no.of possible outcomes)

(No.of favorable outcomes)

=

12

C

1

9

C

1

=

12

9

=

4

3