Question

AbalI is thrown vertically up Ward with velocity of 6m/s. How long does it take for the ball return back to initial position

Answer 1

$\boxed{\sf {\green{Answer}}}$

Time = 0.6sec

$\boxed{\sf {\green{Explanation}}}$

Given:

• S = 0
• V = 0
• u = +6m/s
• a = -g

To Find:

time taken by the body to reach its initial position

Solution:

w.k.t,

$\blue{\boxed{\bold {\pink{{V = u + at}}}}}$

$\mathsf{0 = 6 + (-10) t}$

$\mathsf{0 = 6 -10t}$

$\mathsf{ 10 t} = 6$

$\mathsf{ t = \dfrac{6}{10}}$

$\mathsf{ t= 0.6 sec}$

$\texttt{\red{Aravind}\: \blue{Reddy}....! }$♥

Answer 2

$\huge{\bold{\underline{\underline{....Answer....}}}}$

$\huge{\bold{\underline{Given:-}}}$

u = 6 m/s.

g = - 10 m/s².

t = ?.

$\huge{\bold{\underline{Explanation:-}}}$

As the body is thrown upward and when it comes back it's final velocity will be zero.

Let "t" be the total time when it comes back to its initial position.

Applying First kinematics equation.

$\large{\bold{v = u + at}}$

Substituting the values.

$\large{ 0 = 6 +( - 10 \times t)}$

$\large{0 = 6 - 10t}$

$\large{6 = 10t}$

$\large{t = \frac{6}{10}}$

$\huge{\boxed{\boxed{t = 0.6 \: Seconds}}}$

So,the body comes back to its initial position in 0.6 seconds.