Math, asked by bhaba5996, 9 months ago

Abanis present age is 15 years bigger than himanis present age. 10 years ago abanis age is 4 times than himanis age. What are their present age?

Can anyone do it?​

Answers

Answered by swastik3424
1

Step-by-step explanation:

For explanation, please see the picture above.

Attachments:
Answered by Anonymous
13

Solution :

Let's

Himani's present age = x

Abani's present age = x + 15

Himani's age 10 year ago = x - 10

Abani's age 10 year ago = x + 15 - 10 = x + 5

According to question :

 \implies\sf 4(x - 10) = x  + 5\\  \\\implies \sf 4x - 40 = x  +  5 \\  \\ \implies\sf 4x - x =  5 + 40 \\   \\ \implies \sf 3x = 45 \\   \\\implies  \sf x =  \frac{45}{3}  \\  \\ \large   \boxed{ \sf \green{x = 15}}

Himani's present age = 15 years

Abani's present age= 15 + 15 = 30 years

10 year ago Himani's age is 5 years and Abani's age is 20 years which is 4 times of Himani's age.

Hence Our answer is correct

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