Abattery of e..f 6V and internal resistance 2 ohm is connected in parallel with another battery of e.m.f. 5V and internal resistance 2 ohm. The combination is used to send current through an external resistance of 8 ohm. Calculate the current through the external resistance.
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Explanation:
V1=4v
R1=1Ω
V2=1v
R2=0Ω
'Total current from the combination=current flowing 2Ω=I
∴I=R1−R2v1−v2=1+04−1A
=3A
Potential difference across 2Ω=(3×2)v
=6v
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