Question

Abattery of e..f 6V and internal resistance 2 ohm is connected in parallel with another battery of e.m.f. 5V and internal resistance 2 ohm. The combination is used to send current through an external resistance of 8 ohm. Calculate the current through the external resistance.

Answer 1

Answer:

S9l7589ñ:

V 1=4v

R 1 =1Ω

V 2=1v

R 2=0Ω

'Total current from the combination=current flowing 2Ω=I

∴I $\frac{V1 - V2} {R1 - R2} = \frac{4 - 1}{1 + 0} A \\ = 3A$

Potential difference across 2Ω=(3×2)v

$= 6V$