Question

Abbad is three years older than Shafaque. Six years
ago, Abbad's age was four times Shafaque's age.
Find the age of Abbad and Shafaque.​

Answer 1

Answer:

if shafaque =x

then ,Abbad = x+3

6 years ago, shafaque =x

then , Abbad = 4x

so, after 6 years , shafaque= X+6

Abbad= 4X+6

X+X+3 = X+6+4X +6

2X +3 =5X +12

5X -2X =12-3

3X = 9

X=9/3 = 3

Abbad= X+6

3+6=9 years old

shafaque = 4*3+6

12+6

=18 years old.