Abbad is three years older than Shafaque. Six years
ago. Abbad's age was four times Shafique's age
Find the age of Abbad and Shafaque
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SOLUTION :-
Let the age of Abbad be x
the age of Shafaque be y.
x= y+3 ....(1)
six years ago,
(x-6) = 4(y-6)
x-6 = 4y-24
x-4y = -18 ....(2)
Subtracting (1) & (2),
3y = 21
y = 7
x = 10
Therefore, the age of Abbad is 10
the age of Shafaque is 7.
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