Abbas Travels a distance 120 km with a speed of 40 kilometre per hour and returns with a speed of 30 km per hour calculate the average speed for the entire train journey
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total distance = 120 * 2 = 240 km (because, 120 is for one journey)
speed1 = 40km/h
speed2 = 30km/h
avg.speed = total distance/total time taken = ?
s1 = 40
d1 = 120km
t1 = d1/s1 = 120/40 = 3h
s2 = 30
d2 = 120km
t2 = d2/s2 = 120/30 = 4h
hence, avg.speed = total distance/total time taken = 240/(3+4)h = 240/7 =
34.2857 km/h
....hope this helps you......do rate and mark as brainiest if this helps you............... ^_^
speed1 = 40km/h
speed2 = 30km/h
avg.speed = total distance/total time taken = ?
s1 = 40
d1 = 120km
t1 = d1/s1 = 120/40 = 3h
s2 = 30
d2 = 120km
t2 = d2/s2 = 120/30 = 4h
hence, avg.speed = total distance/total time taken = 240/(3+4)h = 240/7 =
34.2857 km/h
....hope this helps you......do rate and mark as brainiest if this helps you............... ^_^
tejasgupta:
Please mark my answer as brainiest....
Answered by
4
total distance=240
total time taken by object to cover total distance=7 hours
now,
average speed=(total distance)/(total time)
=( (240)/(7) ) km/hour
=( (3.285714....) )km/hour
total time taken by object to cover total distance=7 hours
now,
average speed=(total distance)/(total time)
=( (240)/(7) ) km/hour
=( (3.285714....) )km/hour
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