Math, asked by semwalupasana, 7 months ago

abc = 100a+10b + c
cab = 100c + 10a + b
bca = 100b + 10c + a
abc + cab + bca = 111(a+b+c)

Answers

Answered by sundarvenkatsundarve

1

Step-by-step explanation:

100a+10a+a=111a

100b+10b+a=111b

100c+10c+c=1111c

hence,abc+cab+bca=111(a+b+c)

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