Question

ABC=144,A+B+C=19;A,B,C=?

Answer 1

Answer:

incomplete question...

there should be 3 different equations for solving 3 different variables..

Answer 2

The question is incomplete and assuming the question is to find the solution triplets where A,B,C are natural numbers

(2,8,9) and (3,4,12) are solution triplets.

Explanation:

Given ABC=144 and A+B+C=19

on factorisation of 144 as a product of 3 natural numbers and checking whether the sum is 19 or not.

144= 2*72=2*2*36=2*3*24=2*4*18=2*6*12=2*8*9(2+8+9=19)

3*48=3*2*24=3*3*16=3*4*12=3*6*8(3+4+12=19)

4*36=4*2*18=4*3*12=4*4*9=4*6*6(repeated 3,4,12)

6*24=6*2*12=6*3*8=6*4*6(no solution)

8*18=8*2*9=8*3*6(repeated 2,8,9)

9*16=9*2*8=9*4*4 (repeated 2,8,9)

12*12 (repeated 12,3,4)

Therefore the solution sets are (2,8,9) (3,4,12)