ABC=60 ACB =54
BE and CD bisects ABC
and ACB respectively.
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Answer:
to find : value of x
angle ABC =60
ANGLE OBC = 60/2 =30⁰ ( BE bisects angle ABC)
ANGLE OCB = 54/2 =27⁰ (CD bisects angleACB)
Now,
in triangle OBC,
OBC + OCB + x = 180⁰ (angle sum property of triangle)
30⁰+27⁰+x =180⁰
57⁰+x = 180⁰
x = 180⁰ - 57⁰
x =123⁰
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