abc=8 then what is the minimum value of(1+a)(1+b)(1+c)
Answers
Answered by
5
If abc=8, the minimum value of (1+a)(1+b)(1+c) is 27, assuming a, b, and c are equal.
2*2*2=8
Therefore a=2, b=2, and c=2.
We can then substitute these values in the equation (1+a)(1+b)(1+c)
(1+2)(1+2)(1+2)
(3)(3)(3)
(9)(3)
27
Therefore the minimum value of (1+a)(1+b)(1+c) is 27 if abc=8
2*2*2=8
Therefore a=2, b=2, and c=2.
We can then substitute these values in the equation (1+a)(1+b)(1+c)
(1+2)(1+2)(1+2)
(3)(3)(3)
(9)(3)
27
Therefore the minimum value of (1+a)(1+b)(1+c) is 27 if abc=8
Similar questions