∆ABC
a=18,b=24,C=30 find cos B
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(a)^2+(b)^2
=(18)^2+(24)^2
=324+576
=900
=(30)^2
=(c)^2
So,(a)^2+(b)^2=(c)^2
So ∆ABC is right angled at the angle between a and b which is angle B
Now,
CosB=Base/Hypothenuse
=b/c
=24/30
=4/5 or 0.8
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