Math, asked by Anonymous, 4 months ago

abc + ab2 c + 2acb2 + 3c2 ab + b2 ac − 2a2 bc + 3cab2

Answers

Answered by satendary98399
3

Answer:

+3abc+3a2b+e

Plz Mark as brailiest answer

Answered by TheBrainlyopekaa
35

Step-by-step explanation:

\begin{gathered}\begin{gathered}\boxed{\begin{array}{c|cc}\sf Class\: interval&\sf Frequency\: (f)\\\frac{\qquad \qquad \qquad \qquad}{}&\frac{\qquad \qquad \qquad \qquad}{}\\\sf 40 - 50&\sf 5\\\\\sf 50 - 60 &\sf x\\\\\sf 60-70 &\sf 15\\\\\sf 70 - 80&\sf 12\\\\\sf 80-90&\sf 7\\\frac{\qquad \qquad \qquad \qquad}{}&\frac{\qquad \qquad \qquad \qquad}{}\\\sf & \sf \sum f = 67& \end{array}}\end{gathered}\end{gathered}

Classinterval

40−50

50−60

60−70

70−80

80−90

∑f=67

We know that :-

Sin 60° = √3/2

Cos 30° = √3/2

Sin 30° = 1/2

cos 30° = 1/2

tan 45° = 1

____________________

Trigonometric table :-

\begin{gathered}\begin{array}{ |c |c|c|c|c|c|} \bf\angle A & \bf{0}^{ \circ} & \bf{30}^{ \circ} & \bf{45}^{ \circ} & \bf{60}^{ \circ} & \bf{90}^{ \circ} \\ \\ \rm sin A & 0 & \dfrac{1}{2}& \dfrac{1}{ \sqrt{2} } & \dfrac{ \sqrt{3} }{2} &1 \\ \\ \rm cos \: A & 1 & \dfrac{ \sqrt{3} }{2}& \dfrac{1}{ \sqrt{2} } & \dfrac{1}{2} &0 \\ \\ \rm tan A & 0 & \dfrac{1}{ \sqrt{3} }& 1 & \sqrt{3} & \rm Not \: De fined \\ \\ \rm cosec A & \rm Not \: De fined & 2& \sqrt{2} & \dfrac{2}{ \sqrt{3} } &1 \\ \\ \rm sec A & 1 & \dfrac{2}{ \sqrt{3} }& \sqrt{2} & 2 & \rm Not \: De fined \\ \\ \rm cot A & \rm Not \: De fined & \sqrt{3} & 1 & \dfrac{1}{ \sqrt{3} } & 0 \end{array}\end{gathered}

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