ABC-ADEF, I HABC) ALADEFY-12 & AB-4, then to find DE. Complete the following activity
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The sum of the ages of a father and his son is 120 years. If the father's age is 5 times the son's age then find the son's age.
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∆ ABC ~ ∆ DEF
A (∆ABC)/ A(∆DEF) = AB²/DE²
1/2 = 4²/DE²
1/2 = 16/DE²
Therefore, DE²= 16×2
DE= 4√2
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