Question

∆ABC &∆ADC are two right triangles with hypotenuse AB&AD respectively given that AB=20 M AC= 15M & area of ∆ABC=240meter square find height
Please solve fast TQ
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Answer 1

Step-by-step explanation:

AC is the common hypotenuse. ∠B=∠D=90°.

To prove,

∠CAD=∠CBD

Proof:

Since, ∠ABC and ∠ADC are 90°.

These angles are in the semi-circle.

Thus, both the triangles are lying in the semi-circle and AC is the diameter of the circle.

⇒ Points A,B,C and D are concyclic.

Thus, CD is the chord.

⇒∠CAD=∠CBD ...Angles in the same segment of the circle