∆ ABC & ∆ DEF are equilateral triangle, If A(∆TBC); A(∆DEF) = 1:2 & AB= 4 find DE.
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the answer of this is DE= 32
explanation:
A(∆ABC): A(∆DEF) = AB^2 / DE^2
therefore,
1/2= 4^2 / DE
DE= 16×2
therefore,
DE=32...... by theorem of areas of similar triangles
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