Math, asked by janvimishra1313, 3 months ago

abc and ADC are two equilateral triangle on a common base ac . find the angle of the resulting quadrilateral. show that it is a rhombus.

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Answered by eshu001
2

Answer:

hey mate

Step-by-step explanation:

ΔABC and ΔADC are two equilateral triangles on a common base AC.

In triangle ABC, AB=AC=BC and in triangle ADC, AD=AC=DC

From this we get two triangles ABC and ADC are Equilateral Triangles with same side.

The equilateral triangle have some angle which is equal to 60°

Here AC is the common base, we get a quadrilateral ABCD.

<A=60°+60°= 120°, <B=60°, <C=60°+60°=120° and <D=60°

Also AB=BC=CD=AD

All the sides of this quadrilateral are equal , so it is a rhombus

Answered by aanyasharma9
3

Answer:

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