ABC and ADC are two equilateral triangles on a common
base AC. Find the angles of the resulting
quadrilateral. Show that it is a rhombus.
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Height of the cylindrical part =13cm
Radius of cone , cylinder and hemi sphere=5cm
r=5cm for hemisphere cylinder and cone.
Height of cone h=30−5−13=12
The area of canvas required=Surface area of hemishphere,cylinder and cone parts of tent
A=2πr
2+2πrH+πr( h2 +r2 )A=2π×5×5+2π×5×13+π×5( 5 2 +122 ) A=770cm2
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∆s ABC and ADC are equilateral
AB = BC = CD = AD = AC
and also ∠B = ∠D = 60°
Now, ∠A = ∠BAC + ∠CAD = 60° + 60° = 120°
and ∠C = ∠ACB + ∠ACD = 60° + 60° = 120°
All of its side are equal. Therefore it is a rhombus
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