ABC and ADC are two equilateral Triangles on a common base AC find the angles of the resulting Collateral so that it is a rhombus
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Step-by-step explanation:
∴ ∆s ABC and ADC are equilateral
∴ AB = BC = CD = AD = AC
∴∠B = ∠D = 60°
Now, ∠A = ∠BAC + ∠CAD = 60° + 60° = 120°
∴ ∠C = ∠ACB + ∠ACD = 60° + 60° = 120°
∴ All of its side are equal. Therefore it is a rhombus
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