ABC and ADC are two right triangles with common hypotenuse AC. Prove that ∠CAD = ∠CBD.
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i forgot to lable the points B and D
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Hello mate ☺
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Solution:
AC is the common hypotenuse for two right triangles, ∆ABC and ∆ADC.
∠ABC=∠ADC=90° (Given)
⇒∠ABC+∠ADC=180°
(If sum of a pair of opposite angles of a quadrilateral is 180°, the quadrilateral is cyclic.)
Therefore, quadrilateral ABCD is cyclic.
⇒∠CAD=∠CBD. (Angles in the same segment are equal)
I hope, this will help you.☺
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