ABC and ADC are two right triangles with common hypotenuse AC. Prove that
CAD=CBD
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➡️AC ɪs ᴛʜᴇ ᴄᴏᴍᴍᴏɴ ʜʏᴘᴏᴛᴇɴᴜsᴇ. ∠B=∠D=90°.
➡️Tᴏ ᴘʀᴏᴠᴇ,
➡️∠CAD=∠CBD
Pʀᴏᴏғ:
➡️Sɪɴᴄᴇ, ∠ABC ᴀɴᴅ ∠ADC ᴀʀᴇ 90°.
➡️Tʜᴇsᴇ ᴀɴɢʟᴇs ᴀʀᴇ ɪɴ ᴛʜᴇ sᴇᴍɪ-ᴄɪʀᴄʟᴇ.
➡️Tʜᴜs, ʙᴏᴛʜ ᴛʜᴇ ᴛʀɪᴀɴɢʟᴇs ᴀʀᴇ ʟʏɪɴɢ ɪɴ ᴛʜᴇ sᴇᴍɪ-ᴄɪʀᴄʟᴇ ᴀɴᴅ AC ɪs ᴛʜᴇ ᴅɪᴀᴍᴇᴛᴇʀ ᴏғ ᴛʜᴇ ᴄɪʀᴄʟᴇ.
⇒ Pᴏɪɴᴛs A,B,C ᴀɴᴅ D ᴀʀᴇ ᴄᴏɴᴄʏᴄʟɪᴄ.
➡️Tʜᴜs, CD ɪs ᴛʜᴇ ᴄʜᴏʀᴅ.
⇒∠CAD=∠CBD ...Aɴɢʟᴇs ɪɴ ᴛʜᴇ sᴀᴍᴇ sᴇɢᴍᴇɴᴛ ᴏғ ᴛʜᴇ ᴄɪʀᴄʟᴇ
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