ABC and ADC are two right triangles with common hypotenuse AC.Prove that angle CAD=angle CBD
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Ac is common and it’s hypothenuse And angle b and d are right angled And AB line is congruent to AD
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Hello mate ☺
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Solution:
AC is the common hypotenuse for two right triangles, ∆ABC and ∆ADC.
∠ABC=∠ADC=90° (Given)
⇒∠ABC+∠ADC=180°
(If sum of a pair of opposite angles of a quadrilateral is 180°, the quadrilateral is cyclic.)
Therefore, quadrilateral ABCD is cyclic.
⇒∠CAD=∠CBD. (Angles in the same segment are equal)
I hope, this will help you.☺
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