Question

ABC and AMP are two right angled triangles, right angled at B and M Respectively. Prove that:(i) ∆ABC~∆AMP (ii) CA/PA=BC/MP​

Answer 1

Answer:

Answer

In ∆ABC and ∆AMP,

∠ABC=∠AMP=90°

∠A is common

∴ By AA criterion of similarity, ∆ABC ∼ ∆AMP

∴ CA/PA = BC/MP (Corresponding Sides of Similar Triangles)

Hence Proved -