Question

ABC and BDE are two equilateral traingles such that D is the mid point of BCfind ratio ofareas of the traingles

Answer 1

We know that area( equilateral triangle)= √3a²/4 , where a is the side of the triangle.

If each side of tri ABC = 2a unit

Then, Area (triABC) = √3 a² ……….. (1)

Now, BD = BC/2 ( given)

=> BD = 2a/2 = a

So, area( equilateral triangle BDE)=√3a²/4 ….(2)

By dividing (1) by (2)

ar( tri ABC) / ar(tri BDE) = (√3a²*4)/ √3a² = 4/1

= 4 : 1

Answer 2

1:2 will be the answer
ratio of sides is equal to the given the ratio of area of triangle