ABC and BDE are two equilateral triangle such that BD=2\3 BC. Find the ratio of area triangle ABC and BDE.
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Given➡BD=2/3 BC
➡BC/BD=3/2
since the equilateral triangles are similar by AAA similarlity (all angles 60°)
and as we know that the areas of the two similar triangles are in the ratio of the squares of any of their corresponding sides.
therefore➡(BC/BD)^2=ar(ABC)/ar(BDE)
➡(3/2)^2= ar(ABC)/ar(BDE)
➡9/4= ar(ABC)/ar(BDE)
hence their ratio is 9:4
➡BC/BD=3/2
since the equilateral triangles are similar by AAA similarlity (all angles 60°)
and as we know that the areas of the two similar triangles are in the ratio of the squares of any of their corresponding sides.
therefore➡(BC/BD)^2=ar(ABC)/ar(BDE)
➡(3/2)^2= ar(ABC)/ar(BDE)
➡9/4= ar(ABC)/ar(BDE)
hence their ratio is 9:4
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