ABC and BDE are two equilateral triangle such that D is the mid-point of bc. ratio of areas of triangle ABC and BDE is
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ABC and BDE are two equilateral triangles such that D is the mid point of BC. What is ar (ABC) : ar (BDE)?
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ABC and BDE are two equilateral triangles such that D is the mid point of BC. What is ar (ABC) : ar (BDE)?
We know that area( equilateral triangle)= √3a²/4 , where a is the side of the triangle.
If each side of tri ABC = 2a unit
Then, Area (triABC) = √3 a² ……….. (1)
Now, BD = BC/2 ( given)
=> BD = 2a/2 = a
So, area( equilateral triangle BDE)=√3a²/4 ….(2)
By dividing (1) by (2)
ar( tri ABC) / ar(tri BDE) = (√3a²*4)/ √3a² = 4/1
= 4 : 1
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