ABC and BDE are two equilateral triangles such that D is the mid-point of BC. Ratio of
areas of triangles ABC and BDE is
(A) 2:1
(B) 1:2
(C) 4:1
(D) 1:4
Answers
Answered by
2
Answer:
it is (c) 4:1
Step-by-step explanation:
Given: △ABC and △BDE are equilateral triangles.
D is midpoint of BC.
Since, △ABC and △BDE are equilateral triangles.
All the angles are 60
∘
and hence they are similar triangles.
Ratio of areas of similar triangles is equal to ratio of squares of their sides:
Now,
A(△ABC)
A(△BDE)
=
BD
2
BC
2
A(△BDE)
A(△ABC)
=
BD
2
(2BD)
2
....Since BC=2BD
A(△BDE)
A(△ABC)
=4:1
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