ABC and BDE are two equilateral triangles such that D is the midpoint of BC ratio of the areas of triangles ABC and BDE is
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2 is to1 is the ratio of the areas
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Let side of triangle ABC=x Therefore, side of triangle BDE= x/2 Area of equilateral triangle= √3 (side)²/4 Area of ABC= √3 x²/4 Area of BDE= √3 (x/2)²/4 = √3 x²/16 Area ABC/ Area BDE= (√3x²/4)/(√3x²/16) = 4/1 Ratio is 4:1
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