ABC and CDE are congruent equilateral triangle . if the measure of the angle ACD is 80 degree , what is the measure of angle of ABD
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Step-by-step explanation:
Yeah we can easily say angle B without any inequalities.
Just think that from a point(one of the veritices) you are drawing 2 lines by making an angle of 80 degrees and which are equal in length.
Let that starting point will be as A and those other drawn lines are B and C. Now if you Join those points(vertices) B and C means that will make equal angles with AC and AB.
Now we can easily derive the angle of B. Total angle of triangle is 180 degrees and of that A is 80 degrees, then other two angles sum will be 100 degrees. As I said in the above Angle of B and C are equal then angle of B is 50 degrees ( half of that 100 degrees)
Hope you understand what I am trying to say without any inequalities.
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