Question

Abc and dbc ar triangles on base bc prove ar abc /ar dbc =ao/do

Answer 1

Answer:

Step-by-step explanation:

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Ar. of ∆ = ½×b×h

NOW,

ar. ∆ ABC = ½ × BC × AO

Also,

ar. ∆ DBC = ½ × BC × OD

So,

\frac{ar. \: ABC}{ar. \: DBC} = \frac{AO}{DO} \\ ............(\frac{1}{2} \: and \: equal \: base \: BC \: are \: cancelled)

✔HENCE PROVED ✔

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