Question

ABC and DBC are two isocelus triangle on the same base bc show that angle abd =acd

Answer 1

Answer:

Step-by-step explanation:

angle abc = angle acb (angles of an isosceles triangle) eq 1

angle dbc = angle dcb (angles of an isosceles triangle) eq 2

subtracting eq 2 from eq 1

angle abc - angle dbc =angle abc -angle dcb

angel abd = angle acd

hence proved.