Question

ABC and DBC are two isosceles triangle on the same base BC(see fig.7.33).Show that ∆ABD=∆ACD​

Answer 1

Answer:

in ∆ABC,

side ba=can,

in ∆bdc

side bd=dc

let the angle abc be x

as we know

angle abc=angle acb,

then acb is also x,

and same for ∆bdc

let the angle dbc be y

as we know

angle bdc=angle dcb,

then dcb is also y

now angle abd= angle acd..........(xy=xy)

by sas

∆ABD=∆ACD

H.P

Answer 2

see this pic its also helps you dude