Question

ABC and DBC are two isosceles triangle on the same base BC show that angle ABD equal to angle ACD​

Answer 1

Answer:

Without loss of generality, suppose A is higher than D (otherwise just swap the labels around).

Then

∠ABD

= ∠ABC - ∠DBC

= ∠ACB - ∠DCB  (since the triangles are isosceles)

= ∠ACD

Answer 2

Hello mate ☺

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$\bold\red{Solution:}$

AB=AC                  (Given)

It means that ∠ABC=∠ACB   (In triangle, angles opposite to equal sides are equal) .....(1)

BD=DC             (Given)

It means that ∠DBC=∠DCB    (In triangle, angles opposite to equal sides are equal)  ......(2)

Adding (1) and (2), we get

∠ABC+ ∠DBC=∠ACB+∠DCB

⇒∠ABD=∠ACD

I hope, this will help you.☺

Thank you______❤

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